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Interesting mathematics problem junior high school mathematics
Two buyers, A and B, went to a feed company twice to buy feed. The price of feed has changed twice, and the two buyers buy feed in different ways. Among them, every time Party A buys 1000kg, every time Party B uses it in 800 yuan, it doesn't consider how much feed to buy.

① What is the average unit price of feed purchased by Party A and Party B?

(2) Whose purchase method is more reasonable?

Solution:

(1)∫A 1000kg each time, the unit price of feed purchased twice is m yuan /kg and n yuan /kg respectively.

∴ Party A pays (1000m+ 1000n) to purchase twice,

Buyer B is in 800 yuan every time he spends money, no matter how much feed he buys.

∴ Party B buys (800/ m3 +800/ m3) kilograms in two times,

∴: The average unit price of feed purchased by Party A twice is (1000 m+1000 n)/2000? =(m+n)/2 yuan/kg,

∴ The average unit price of feed purchased by Party B twice is 2/(1/m+1/n) = 2mn/(m+n)? Yuan/kg;

(2) according to the meaning of the question? (m+n)/2-2mn/(m+n)=[(m+n)^2-4mn]/(2mn)=(m_n)^2/(2mn)

∫m, n is a positive number, m≠n,

∴(m-n)^2>0,

∴(m_n)^2/(2mn)>0,

∴(m+n)/2>; 2mn/(m+n),

The average price of feed purchased twice by B is low, and the second way is reasonable.

As shown in the figure, it is known that in △ABC, AB=AC, ∠ BAC = 90, the straight lines passing through B and C respectively are vertical lines, and the vertical feet are E and F respectively, so I draw my own diagram.

(1) verification: △ Abe △ caf;

(2) When the straight line passing through A does not intersect with the hypotenuse BC, try to explore the relationship among the three line segments EF, BE and CF;