Solution: From f(x+3)=f(x), it is concluded that 3 is the period of the function.
Since f(2)=0, if x ∈ (0 0,6),
It can be concluded that f(5)=f(2)=0,
And if f(x) is odd function, then f(-2)=-f(2)=0,
F(4)=f( 1)=f(-2)=0,
The function f(x) is the odd function defined on R, and it can be concluded that f(0)=0.
So f(3)=f(0)=0, when f(x+3)=f(x),
Let x=-3/2 and get f(-3/2)=f(3/2).
According to the fact that f(x) is a odd function defined on R, it is concluded that f(-3/2)=-f(3/2),
Let f(3/2)=-f(3/2), that is, f(3/2)=0,
So f(9/2)=f(3/2+3)=f(3/2)=0,
So f (9/2) = f (3/2) = f (4) = f (1) = f (3) = f (5) = f (2) = 0, if x ∈ (0 0,6).
So the answer is: 7.