Previously, we learned the percentage application (1) and (2). Now the teacher didn't teach us the percentage application (3), but we taught ourselves the percentage application (3). The following is the result of self-study, which may not be so complete. Looking through the book, the original percentage application (3) is about finding the standard quantity (unit "1") for lovers who know the sum of two partial quantities and the corresponding two partial quantities. The problem of finding the standard quantity usually comes across another old friend of ours, "Equation", and I was right. In this lesson, we need to solve this equation. In the examples in the book, I slowly deduced the solution method of this kind of column equation: 1. A% x-b% x = the difference between two parts; (a%-b%) x = the difference between the two parts. Maybe I don't quite understand this. Specifically, X stands for standard quantity; % represents the percentage of the larger part; B% represents the percentage of the smaller part. I don't know if you understand this. If you don't understand, please wait until I finish studying math diary. That article will be more complete than mine. Stay tuned!

The knowledge encountered in mathematics before was a "new friend" at that time, but now it is an "old friend" for those knowledge. We should review "old friends" and learn "new friends", so that math learning will be interesting! Math diary (1) Percent Application Summary (2) Six (2) Banqiu

This week, we learned the percentage application (1) and (2). These two applications are not difficult to learn, because we have laid the foundation for these in the fifth grade, so we learned them very easily this week.

The application of percentage (1) is mainly to learn how much one number is more than another. There are two solutions to this kind: 1. Find the difference first and then divide it by the unit "1" (for example, the third question on page 32 of the book). 2. Find the unit "65438+" to know the difference. Percentage application (2) mainly studied the topic "Find the quantity corresponding to the known unit'1'"that I learned before. There are two solutions to this problem: 1. Unit' 1 '×( 1+ several percent) 2. Unit' 65438+. The second is to find out how many kilometers you have walked per hour than before. ) pay attention to the use of appropriate methods in appropriate topics. For example, using the second method requires less calculation, so it is better to use the second method. But if you want to use it for your hobby, there is no problem, but solving problems in a simpler way is equivalent to solving difficulties in life in the simplest way.

The percentage is really interesting. I believe we will continue to play with it and study with it next week. I also believe that after the sixth grade, I will definitely learn percentages again in the future; I will also believe that percentages can be seen everywhere in our lives. The application of percentage in math diary (2) Six (2) Ban Qiu Last time we broke through the "first door of percentage", this time we will continue to visit our friends and knock on the "second door of percentage" again. Knocking on it, I found an amiable teacher had a question: there was once a train with a speed of 80 kilometers per hour. After speeding up, the train speed is now112km. What's the current speed? This line is very simple for the students who broke through the first door last time, that is, 1 12-80 = 32km, and it is 32 ÷ 80 = 40% in use. We broke into the first pass, and the second pass was still the kind and friendly teacher, who had a similar problem: there was once a train with a speed of 80km/h. How many kilometers does this train run per hour now? This problem is different from the one we met last time. Let's explore slowly. We know that this question is very similar to the one we learned last semester, so it is very simple for us to explore. There are also two ways. The first way is to find out how many kilometers you run every hour. 80× 40% = 32km，80+32 = 1 12km； The second is to ask a few percent of the original speed first. 80×( 1+40%)= 80× 1.4 = 1 12km。 After another pass, the next pass is written by doing these questions: 1. Unit "1"××1%) 2. The fourth level of the unit "1" (unit "1 "× 0%) refers to the general steps of finding the corresponding quantity with the known unit"1":1. Unit'1'was found. 2. Calculate the difference (increase or decrease). 3. Calculate the corresponding quantity. 4. Test and answer. After our exploration, I gained a lot and further "visited" our friends. In the exploration of mathematics, you will gain a lot, and you will have a lot of happiness.