Formulating the time relation equation:

6+(y-6x)/ 1.25 x+ 1 = 15/x+(y- 15)/ 1.25 x+2

X= 15，y= 165。

So: Team A transports 15 tons per hour, and Team A transports 1 1 hour alone.

8. let AB=X, FP=Y, and extend PK, at point m.

∵ quadrilateral ABCD is a square.

∴AB=AD=CD=BC=X

∴S△AED=[(4+X)X]/2

∫CG = BC-BG = X-4

∴S△CGD=[(X-4)X]/2

∵ Quadrilateral FPRK is a square.

∴FR=RK=PK=FP=Y

GF = 4

∴S△KPG=[(4+Y)Y]/2

∫ quadrilateral FEBG and FPKR are squares.

∴∠MBG=∠BGP=∠P=90

∴ rectangular FPME

∴PM=4 KM=4-Y

EM = Y

∴S△EKM=[(4-Y)Y]/2

∴S△DKE=(S square ABCD+S square GFEB+S rectangular FPME)-(S△AED+

S△CGD+S△GPK+S△EMK)=(X∧2+ 16+4Y)-{[(4+X)X]/2+[(X-4)X]/2+[(4+Y)Y]/2+[(4-Y)Y]/2 }

Simplified S△DKE= 16