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Examination questions of eighth grade mathematics competition
Assumption: X performances are required.

2×( 1+ 10%)( 1+ 10%)。 . . . . =2× 1+ 10% x power = 10.

1+ 10% x power = 10÷2=5.

According to the prompt,

In the sixteenth performance, the proportion of funds raised for a single performance is:

(1. 1) to the sixth power = 1. 1) to the sixth power × 10 (1.1) =/kloc.

In the seventeenth performance, the proportion of funds raised for a single performance is:

17 (1. 1) power = 7 (1. 1) power × 10 (1.1) =/.

Therefore, by the time the performance reached 17, the funds raised for a single performance reached 654.38+10,000 yuan.