Orthogonal decomposition method is used to decompose horizontal and vertical forces.

There are f branches in the vertical direction, 1 = mg+f * sin 37 degrees.

In the horizontal direction, F*cos37 degrees -F 1 = M * a 1, and a 1 is the acceleration.

And f 1 = u * f branch 1.

F*cos37 degrees -u * (mg+f * sin 37 degrees) = m * a 1.

10 * 0.8-0.2 *(2 * 10+ 10 * 0.6)= 2 * a 1

a 1= 1.4 m/s^2

When the acceleration time of the object is t 1 = 5 seconds, the speed is v = a1* t1=1.4 * 5 = 7m/s.

The displacement in the accelerated movement stage is s1= a1* t12/2 =1.4 * 52/2 =17.5m..

After the thrust f is removed, the object is subjected to gravity mg, supporting force F and sliding friction f2.

Let the acceleration be a2.

Get F2 = m * a2.

F2 = u * f branch 2 = u * mg

So a2 = u * g = 0.2 * 10 = 2m/s 2.

The displacement in the deceleration stage is set to S2,

It is 0 = v 2-2 * a2 * S2.

Get 0 = 7 2-2 * 2 * S2.

S2 =12.25m.

The total displacement is s = s1+S2 =17.5+12.25 = 29.75m.