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Do this math problem correctly.
Solution: If you buy X seedlings of B, you buy (600-x) seedlings of A..

( 1)60 *(600-x)+80x & lt; =44000

36000-60x+80x & lt; =44000

20x & lt=8000

X & lt=400 (tree)

You can buy up to 400 B.

(2) If the cost of buying saplings is Y yuan, then y=60*(600-x)+80x.

[0.96 x+0.88 *(600-x)]/600 & gt; =0.9

(0.96 x+528-0.88 x)/600 & gt; =0.9

0.08 x+528 & gt; =540

0.08x & gt= 12

x & gt= 150

y=60*(600-x)+80x

Pack up, take it

y=36000+20x

From this equation (it is best to draw a picture)

When x= 150, the value of y is the smallest.

Y=36000+20* 150, y=39000 (yuan)

A: You should buy 150 seedlings of B and 450 seedlings of A, with a minimum cost of 39,000 yuan.