=3333×6666+3333×3334

=(6666+3334)×3333

= 10000×3333

= 3330000 The third question 525525/252525× 525252/252252 = 21021* 25/101* 25×

=2 102 1/ 10 10 1× 13 13 13/2 102 1*3

= 13 13 13/ 10 10 1*3

= 13* 10 10 1/ 10 10 1*3

= 65438+3/03 The number of the first question can be represented by 3N+2.

When N=0-2

N= 1 - 5

N=2 - 8

N=3 - 1 1

......

N= 19 - 59

Starting from 2, a number ***20, the difference between two adjacent numbers is 3, and = (prefix+mantissa) * number of items /2.

That is (2+59)*20/2=6 10.

You can set this formula when you encounter such a problem in the future.