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On Pythagorean Theorem in the Second Volume of Mathematics Problems in Grade Eight
Fold AD to get AF, so AF=AD= 10, because AB=8, from Pythagorean theorem, there are ABF and AB*AB+BF*BF=AF*AF, and BF=6, then FC=BC-BF= 10-6=4.

EF is obtained by folding DE, so EF=DE. EC = DC- DE =8-ED, using Pythagorean theorem to find triangle CEF;

CF*CF+CE*CE=EF*EF, and if the above relationship is taken into account, there is 4*4+(8-ED)*(8-ED)=ED*ED, which can be solved. If ED=5, then EC=8-5=3cm.