( 1)δ= 4-4a & gt； 0a & lt； By combining 1 with a≠0, we can know a∈(-∞, 0)∩(0, 1).

(2) There are two different solutions, namely A.

f(x)=0 (x- 1/a)？ = 1/a？ -1x = 1/a root number (1/a? - 1)

So there is 0.

Solution 0

Solution 1/a- radical sign (1/a? - 1)& lt； 1 root sign (1/a? -1)> 1/a- 1 note1/a-1>; 0 so 1/a? - 1 & gt； 1/a？ -2/a+ 1 2/a & gt； Because of a man

Solution 1 < 1/a+ radical sign (1/a? -1) has a root sign (1/a? -1) > 0>1-1/a has been satisfied.

Solve the root sign of 1/a+ (1/a? - 1)& lt； 2 has a root sign (1/a? - 1)& lt； 2- 1/ A Zhi 0 and1/a? - 1 & lt； (2- 1/a)？ =4-4/a+ 1/a？

Get a> 1/2 and a >；; 4/5 So there is a & gt4/5.

Comprehensive 4/5