1. Using the relationship between roots and coefficients, the second equation can be obtained as (3/a1)-1-(2/a1) =-b1/a1= 65438.

because

The two roots of equation a1x 2+b1x+c1= 0 are equal.

So b12-4a1* c1= 0.

So a 1*c 1= 1/4.

And because two equations a1x 2+b2x+c1= 0 (a1≠ 0) are 1-A 1,1+a/kloc-0.

So by a 1*c 1= 1/4.

And (1-a1) * (1+a1) =1-a12 = c1/a1.

At the same time, the roots of a 1= plus or minus 2 and c 1 = plus or minus 4 are found (note that the signs of a 1 and c 1 are corresponding).