Current location - Training Enrollment Network - Mathematics courses - The answer to the first volume of the eighth grade mathematics textbook of Beijing Normal University.
The answer to the first volume of the eighth grade mathematics textbook of Beijing Normal University.
Beijing Normal University Edition Eighth Grade Mathematics Textbook Volume 1 Answer (1) Exercise 2.3

1: solution (1)? 49=7; (2) ? (25/ 196)=5/ 14; (3) ? 0.09=0.3; (4)-? 64=-8.

2. Solution: Because 1 1? = 12 1, so the arithmetic square root of 12 1 is1,that is? 12 1= 1 1; Because (3/5)? =9/25, so the arithmetic square root of 9/25 is 3/5, that is? (9/25)=3/5; Because 1.4? = 1.96, so the arithmetic square root of 1.96 is 3/5, that is? (9/25)=3/5; 1.4? = 1.96, then the arithmetic square root of 1.96 is 1.4, that is? 1.96= 1.4; Because (10? )? = 10 6, so? (〖 10〗^6 )= 10? .

3. solution: let the side length of the square be x and the area be a, and get x from the square area formula. = A. When the area of a square becomes four times the original, then 4a=4x? =(2x)? So its side length has doubled. Similarly, when the area becomes 9 times of the original, its side length becomes 3 times of the original; When the area becomes 100 times, its side length becomes 10 times; When the area is n times the original, its side length becomes the original? N times.

Beijing Normal University Edition Eighth Grade Mathematics Textbook Volume 1 Answer (2) Exercise 2.5

Answers to the eighth grade mathematics textbook published by Beijing Normal University (3)