1 divided by10 =110 =1/6 * 4
1-2/3= 1/3 =2/3 A: Four hours later, the two cars have covered two thirds of the whole journey. How many parts are left?
2, 5/8-1/2 =1/8 (km) c = (a+b) * 2 = (5/8+1/8) * 2 = 3/4 * 2 = 3/2 (km).
3. 1 divided by10 =110115 * 5 =1/3.
1 divided by 1 5 =1110 * 5 =1/2 a: A completed 1/3 of this road.
4. 1+4=5 (segment) 20* 1/5=4 (cm) 1 divided by 5= 1/5 A: each segment is 4 cm long, and each segment is 1/5 of the total length.
5.15 ÷ 3 ÷ 2 = 5 ÷ 2 = 2.5 (m) s = π RR = 3 * 2.5 * 2.5 = 18.75 (square meters) A: The maximum area of the henhouse is1.
6,3/4-3/4 *1/4 = 3/4-3/16 = 9/ 16 A: There are 9/16 left.
7, 34÷ 100=0.34 (kg) 1÷0.34=50/ 17 (kg) A: It takes 50/65438+ to squeeze out 0.34 kg of soybean oil per kg.
8. 1 80 ÷12 =15 (L)1divided by15 =115 (L) A: Line/.
9,40-3 = 37 (tree) 37÷40=37/40 3÷37=3/37
A: The surviving trees account for 37/40 of the total trees, and the dead trees account for 3/37 of the surviving trees.
10,3-1= 2 (times) 7÷2=3.5 (minutes) A: It takes an average of 3.5 minutes to saw once.
1 1, 5/6 * 2/2 =10/210/12 * 3/3 = 30/36 A: The original score was 30/.
12,21+14 = 35 (person) 35÷5=7 (person) A: There are at most 7 people in each group, and each group can be divided into 5 groups.
13, 10÷2=5 (species) A: * * * * There are five different sitting methods.
14,30 = 5 * 2 * 3 24 = 2 * 2 * 3 The greatest common factor of 30 and 24 is 2*3=6.
30*24÷(6*6)=720÷36=20 (pieces) A: The side length of a cut square is 6 cm, and it can be cut into 20 squares.
15,10 = 2 * 5 15 = 3 * 510, and the least common multiple of15 is 2*3*5=30 30*3=60 (minutes) for 60 minutes.
5+ 1=6 (hours) a: It will take at least 30 minutes to start at the same time. The third time two cars leave at the same time is 6 o'clock.
16,72 ÷ (9 * 2)+1= 72 ÷18+1= 4+1= 5 (trees) A: There are five trees that need not be replanted.
17, 47-2 = 45 (a) 39-4 = 35 (a) The greatest common factor of 45 And 35 is 5 a: there are at most 5 students in this group.
The greatest common factor of 18, 12 = 2 * 2 * 38 = 2 * 2 12 and 8 is 2 * 2 = 44+2 * 2+1* 2 = 4+4+2 =/kloc-.
19,105 ÷ 7 =1515+2 =17+4 = 2 1 a: the maximum odd number is 2/kloc-0.
The least common multiple of 20, 5 and 7 is 5 * 7 = 35 July 3 1 day +35 days = September 4 A: See you again on September 4.
2 1, 28-2-2 = 24 22-2 =18 24 = 2 * 3 * 418 = 2 * 3 * 3 A: The maximum side length of a square is 3 cm.
22. Denominator: 24÷(7-4)×7 = 24÷3*7=8*7=56.
Molecule: 24÷(7-4)×4 =24÷3*4=8*4=32 A: This score is 32/56.
23. A: 3 ÷ 4 = 3/4 B: 4 ÷ 5 = 4/5 C: 5 ÷ 6 = 5/6 > 4/5 > 3/4 ∴ C has the highest efficiency.
24. solution: let this natural number be X.
( 1 1+x)/( 16+x)= 2/7
7( 1 1+x)= 2( 16+x)
77-7x=32+2x
9x=45
X=5 A: This number is 5.
25, 72 ÷ (7+2) * 2 = 72 ÷ 9 * 2 = 8 * 2 =1672 ÷ (7+2) * 7 = 72 ÷ 9 * 7 = 8 * 7 = 56a: The original score was.
26， 180- 180 * 1/6 = 180-30 = 150(page) 180- 180 * 1/。
150 >144 > 40 ∴ Xiaohong has seen too much.
27. r=d÷2=6÷2=3 (m) S=πrr=3. 14×3*3=28.26 (square meter) 3+2=5 (m).
S =πr the square of π r; =3. 14*5*5=78.5 (square meter) 78.5-28.26=50.24 (square meter)
A: The area of this pebble road is 50.24 square meters.
28. c = π r+2r = 3.14 * 8+2 * 8 = 25.12+16 = 41.12 (meters) A: He needs to prepare 4.
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