Take this rule as arithmetic progression An=n, that is to say, there are n eggs in the nth bottle A 1= 1 A2=2 A3=3 A4=4. If each phase difference is 1, the tolerance is d= 1. Arithmetic progression's summation formula sn = na1+[n (n-65438+]-n)/2 times 2 1056=2n+n? -No, no? +n- 1056=0 cross multiplication (x-32)(x+33)=0 x=32 or x=-33, x =-33 < 0 (discarded), so it is the 32nd bottle.