h(x)=f(x)-x
Because f (x) >; =x so h(x)>=0
h( 1)=0
So (1, 0) is the fixed point of h(x).
h(x)=a(x- 1)^2
h(- 1)=0+ 1= 1
Brought a= 1/4.
c= 1/4 b= 1/2
2) Symmetry axis of G (x)-(1/2-m)/(1/2) = 2m-1
2m- 1 & gt; = 1 or 2m- 1
8.
C brings AC 2+BC+C = 0.
Ac is not 0.
F( 1/a) brings 1/a+b/a+c=f(c)/a/c=0.
2)a & gt; When 0 F(c), 0 opens up, so c is the smaller root.