h(x)=f(x)-x

Because f (x) >; =x so h(x)>=0

h( 1)=0

So (1, 0) is the fixed point of h(x).

h(x)=a(x- 1)^2

h(- 1)=0+ 1= 1

Brought a= 1/4.

c= 1/4 b= 1/2

2) Symmetry axis of G (x)-(1/2-m)/(1/2) = 2m-1

2m- 1 & gt； = 1 or 2m- 1

8.

C brings AC 2+BC+C = 0.

Ac is not 0.

F( 1/a) brings 1/a+b/a+c=f(c)/a/c=0.

2)a & gt； When 0 F(c), 0 opens up, so c is the smaller root.