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Selection of mathematical problems
The analysis of this topic is an analysis and discussion topic. Xiaoming made a mistake in 65438+ 0/9 of the total number of questions, and made a mistake in 8/9 of the total number of questions. They all got a correct question of 65438+ 0/6 of the total number of questions, because Xiaoying made seven correct questions. According to the least common multiple of 6 and 9, the total number of questions was set to 18k. That is, 18k× 1/6≤7, that is, 3k≤7, so k= 1 or k=2. Then discuss the answers and choose according to the meaning of the questions to get the best answer.

explain

Solution:

Xiao Ming answered the wrong question of 1/9 correctly, and all the answers were 1/6 of the total number of questions, so the total number of questions can be set to 18K.

In this way, this problem becomes: a math exercise, * * * has a 18K problem, A answers the 2K problem incorrectly, Xiaoying answers the 7th problem correctly, and both of them answer the 3K problem correctly. Q: How many questions did Xiao Ming answer correctly?

Obviously, 2K will not exceed 7, so there are only two possibilities: K= 1 and K=2.

When K= 1, the total number of questions is 18, and Xiaoming gets two wrong answers and 16 correct answers; Xiaoying answered seven questions correctly. Both of them answered at least five questions correctly. Obviously, it is contradictory to answer three questions correctly.

When K=2, the total number of questions is 36, Xiaoming answers 4 questions wrong and 32 questions right; Xiaoying answered seven questions correctly. Both of them got 6 right. It's possible. So A got 32 questions right.

A: Xiaoming answered 32 questions correctly.