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A math problem in senior two, the conditions and conclusions have been exchanged, how to prove it?
Extend EB to g

Make BG=DF

∫AE = BE+DF

∴ AE=EG

δAEG is an isosceles triangle.

∴ ∠G=∠EAG

∫δABG?δADF

Bag =∠DAF

∠G=∠AFD

∫AB//CD

∴AFD =∠fab

∴ ∠G=∠FAB

∴ ∠EAG=∠FAB

Bag =∠FAE

Bag =∠DAF

∴ ∠FAE=∠DAF

∴ AF split ∠DAE

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