Dh=6*6/2= 18 is known (the added faces are two identical faces).
So the whole substitution is S=3. 14* 18=56.52.
2. If the radius is r and the height is h, the surface area is S=2*3. 14*r? +2*3. 14 r h
Known square
So 2r=h
Because the circumference (2 * 3.14r+h) * 2 = 2512.
So h=303 r= 15 1.5.
So substitute the surface area S=432420.39 square centimeters =43.24 square meters.
The problem is to find twice the surface area, r=30 h=40.
s = 2 *(2 * 3. 14rh+3. 14r? ) =20724 cm2 =2. 1 m2