Dh=6*6/2= 18 is known (the added faces are two identical faces).

So the whole substitution is S=3. 14* 18=56.52.

2. If the radius is r and the height is h, the surface area is S=2*3. 14*r? +2*3. 14 r h

Known square

So 2r=h

Because the circumference (2 * 3.14r+h) * 2 = 2512.

So h=303 r= 15 1.5.

So substitute the surface area S=432420.39 square centimeters =43.24 square meters.

The problem is to find twice the surface area, r=30 h=40.

s = 2 *(2 * 3. 14rh+3. 14r？ ) =20724 cm2 =2. 1 m2