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Junior high school mathematics. How to solve the problem of opening the root number in the root number (urgent)
Correct your mistakes first.

√ 125=5√5

√ 153=3√ 17

√225= 15

√72=6√2

3√ 18-√32=9√2-4√2=5√2

5√32-√200=20√2- 10√2= 10√2

2√27+3√3-√ 12=

6√3+3√3-2√3=7√3

2√20-√45+√500=

4√5-3√5+ 10√5= 1 1√5

(√3-√2)(√3+√2)=

3-2= 1

(√3-√2)(√3-√20)=

3-2√ 15-√6+2√ 10

(√5-√3)(√5-√3)=

5+3-2√ 15=802√ 15

(2√5+ 1)(√5- 1)=

10-2√5+√5- 1=9-√5

(4√5- 1)(2√5- 1)=

40-4√5-2√5+ 1=4 1-6√5

(√ 1 1-3)(√ 1 1+3)=

1 1-9=2

This part is radical simplification.

3x+4y= 18

5x-3y= 1

x,y

What's the difference

The above formula+the following formula is:

8x+y= 19, y= 19-8x, substitute the following formula.

5x-3( 19-8x)= 1

x=2,

So y= 19-8*2=3.

y=3x+4

3y-x=4

x,y

what's up

Substitute the above formula into the following formula.

3(3x+4)-x=4

X=- 1, so y=3(- 1)+4= 1.

3x-4y=2

x+3y=- 1

x,y

what's up

The following formula is changed to x=- 1-3y and substituted into the above formula.

3(- 1-3y)-4y=2

y=-5/ 13,x =- 1-3 *(5/ 13)= 2/ 13

This part is the solution of binary linear equation.

simplify

x^+5x+6=

(x+2)(x+3)

x^-6x+8=

(x-2)(x-4)

x^-5x-24=

(x-8)(x+3)

3x^-5x+2=(3x-2)(x- 1)

8x^+ 18+7=

(2x+ 1)(4x+7)

6x^- 1 1x- 10=

(2x-5)(3x+2)

5x^-80=

.. this is the simplest one.

. . . . What else do you want?

This part is factorization.

All right, every part has been answered. . .