30-0. 1 1/( 15/3600)= 3.6km。

The speed of students is every hour.

(0. 1 1/ 12/3600)-30 = 3km。

It takes time for two people to meet from 14 to 16.

(30-3.6)*6/60/(3.6+3)=0.4 (hour) =24 minutes

14 hours 16 points +24 points = 14 hours and 40 minutes.

Solution 2: (vehicle speed-working speed) * 15= vehicle length = (vehicle speed+learning speed) * 12,

Then working speed+learning speed = (vehicle speed+learning speed)-(vehicle speed-working speed) = (112-115) * conductor.

14: 00 The train caught up with the workers. 14: 00 When meeting the students,

The distance between workers and students is exactly (speed-working speed) *6=6/ 15* conductor.

In this way, it will take time from now until the workers and students meet.

(6/ 15* captain)/[(112-115) * captain] = (6/15)/(/kloc-)

A: Workers and students will meet at 14: 40.

Solution: the train speed is 30 km/h =25/3 m/s 3 m/s.

Worker speed (15× 25/3-10) ÷15 =1m/s

Student speed (110-12× 25/3) ÷12 = 5/6 m/s.

Time required for workers and students to meet from 14: 00 to 16: 00.

(25/3-1) × 6 ÷ (1+5/6) = 24 points.

So the workers and students gathered at 14: 40.