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The problem of chickens and rabbits in the same cage in grade six
Chickens and rabbits in the same cage were fined ***4, and 8 heads were detained from the bones, 100 feet. How many chickens and rabbits are there?

Solution: There are X rabbits and 48-x chickens.

4x+(48-x)×2= 100

4x+96-2x= 100

2x= 100-96

2x=4

x=2

48-x chickens =48-2=46 chickens.

Method 2: Assuming that all feet are rabbits, 48X4= 192, which is higher than 192- 100=92, because some feet are chickens, rabbits are 4-2=2 more than chickens.

One foot.

These extra feet are 92÷2=46 (chicken) and 48-46=2 (rabbit).

Method 2: Assuming all chickens, then ...

Let smart people handle the rest.

1, set the ship X.

Equation: 9x+(7-x)=50.

2、88- 16=72

72÷

(4+8)=6 Tortoise

sabotage

6+2= 12

three

20x0.08- 1.4=0. 16

6 points =

0. 16÷(8-6)=8

8 o'clock =20-8= 12