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The sixth grade mathematics second volume cylinder application problem:
1, (1) base diameter: 6÷3. 14÷2=0.96dm (two decimal places are reserved).

Cylinder volume: 0.96? x3. 14x2=5.79dm? (Keep two decimal places)

If π≈3

Bottom diameter: 6÷3÷2= 1dm.

Cylinder volume: 3x 1? x2=6dm?

2. Because cutting into four sections will add four sides.

Steel bottom area = 18.84÷4=4.7 1cm?

5dm=50cm

Steel volume =4.7 1x50=235.5cm?

3. 2.5m = 25m

Surface area =3x3. 14x25+(3÷2)? x3. 14x2

=249.63dm?

=2.4963m?