I don't think what is known is useful. The known condition is to draw cards from 52 playing cards, and now you draw cards from 50 playing cards. (it should be assumed that poker has removed the king of size, right? ) So let's start from the beginning.

Now that you have two different cards, six of the remaining 50 cards can match your card, and the remaining 44 cards can't.

If you touch three cards now and just make a "three", there are always two unpaired cards. The probability is:

Write the mark aCb as the combination number of b in a.

2 *(3c 2)(44c 1)/(50 C3)= 33/2420

If you touch three cards now, you can make four identical black and red plum cards, which obviously meets the problem conditions. The probability is:

2*(3C3) / (50C3) = 1/9800

So the total probability is19/1400 =1.36%.