In the plane rectangular coordinate system xOy, there is a parabola y=x2-2x-3, which intersects with the X axis at points B and C (B is on the left side of C), point A is on the parabola, and the abscissa is -2. The back of cantilever AB and AC are exactly the same, and the front is marked with the numbers -2,-1, 0 and 1 respectively.

Solution: ∵ When x2-2x-3=0, the solution is x 1=3, x2=- 1,

∫ Parabola y=x2-2x-3, intersects with X axis at points B and C (B is on the left side of C), the coordinates of point B are (-1, 0), the coordinates of point C are (3,0), point A is on this parabola, and the abscissa is -2.

Then {-2k+b=5.

-k+b=0, the solution is: {k=-5b=-5, and the analytical formula of ∴ straight line AB is: y=-5x-5.

Similarly, the analytical formula of linear AC is: y=-x+3,

According to the meaning of the question, all possible coordinates of point P are: (-2,-1), (-1, 0), (0, 1), (1, 2), (2, 3),

∴ Point P falls within △ABC (including the boundary) (-1, 0), (0, 1), (1, 2),

The probability that point P falls within △ABC (including the boundary) is 3/5.