Again, y=mx, y=2x-x? The intersection of is (0,0), (2m, 2m-m? ), ∴y=mx and y=2x-x? Closed area s1= ∫ (0,2-m) (2x-x? -mx)dx=S/2=2/3 .
And, ∫ (0,2-m) (2x-x? -mx)dx=(2-m)? /6,∴(2-m)? /6=2/3,m=2-2^(2/3)。
For reference.