This problem was discovered by accident. The title of this paper is: Uncle Li has *** 14 banknotes with a total face value of 80 yuan. It is known that there are more banknotes with 1 yuan than those in 2 yuan, 5 yuan. Then, can you figure out how many Zhang Yiyuan, five yuan and ten yuan are in Uncle Li's paper money?
I thought of this problem immediately after I saw it. This question is very difficult. It only tells us the number of banknotes, the total face value and the difference between one yuan and five yuan.
So, I thought for a while, and then calculated step by step. According to what we have learned now, I have made a list:
1 yuan/Zhang, 3, 4, 5, 5 yuan/Zhang, 1, 2, 3, 10 yuan/Zhang, 10, 8, 6, total face value 108, 94.
If Uncle Li has 1 Zhang Wu, because one yuan is two more than five yuan, there are three Zhang Yiyuan banknotes, and the remaining 10 is naturally ten yuan, with a total face value of 108 yuan; If there are two five-dollar bills, then there are four Zhang Yiyuan bills, and the remaining 14-(2+4)=8 bills are 10 yuan, with a total face value of 84 yuan; Suppose there are three five-dollar bills, five Zhang Yiyuan bills and six ten-dollar bills with a total face value of 80 yuan. It just meets the requirements of the topic, so I got the number of notes in this way.
I can't tell you how happy I am that this difficult problem has finally been solved.