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Mathematics solves difficult problems. Write 500 words.
Students, we often encounter some profound problems in our study, which often make us lose our way and find the correct way of thinking. I also met a problem that puzzled me.

This problem was discovered by accident. The title of this paper is: Uncle Li has *** 14 banknotes with a total face value of 80 yuan. It is known that there are more banknotes with 1 yuan than those in 2 yuan, 5 yuan. Then, can you figure out how many Zhang Yiyuan, five yuan and ten yuan are in Uncle Li's paper money?

I thought of this problem immediately after I saw it. This question is very difficult. It only tells us the number of banknotes, the total face value and the difference between one yuan and five yuan.

So, I thought for a while, and then calculated step by step. According to what we have learned now, I have made a list:

1 yuan/Zhang, 3, 4, 5, 5 yuan/Zhang, 1, 2, 3, 10 yuan/Zhang, 10, 8, 6, total face value 108, 94.

If Uncle Li has 1 Zhang Wu, because one yuan is two more than five yuan, there are three Zhang Yiyuan banknotes, and the remaining 10 is naturally ten yuan, with a total face value of 108 yuan; If there are two five-dollar bills, then there are four Zhang Yiyuan bills, and the remaining 14-(2+4)=8 bills are 10 yuan, with a total face value of 84 yuan; Suppose there are three five-dollar bills, five Zhang Yiyuan bills and six ten-dollar bills with a total face value of 80 yuan. It just meets the requirements of the topic, so I got the number of notes in this way.

I can't tell you how happy I am that this difficult problem has finally been solved.