∴x= 1/2*(t- 1/t)x^2+ 1= 1/4*(t^2+ 1/t^2-2)+ 1= 1/4*(t^2+ 1/t^2+2)=[ 1/2*((t+ 1/t)]^2

∴ Original formula = [1/2 * (t-1/t)-1/2 * (t+1/t)] n

=[-2*( 1/2)* 1/t]^n

=(- 1)^n*( 1/t)^n

=(- 1)^n* 1/2007

That is, when n= odd number, the original formula =- 1/2007 (n > 1).

When n= even number, the original formula = 1/2007.

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