Then the inequality [f (x)-f (-x)]/x

That is 2f (x)/x)/x.

That is f (x)/x)/x.

When x>0, f(x) is increasing function, and f(2)=0.

When 0

f(x)/x & lt； 0, the inequality holds.

When x>2 is at o'clock, f(x)>f(2)=0.

f(x)/x & gt； 0, the original inequality does not hold.

According to odd function's symmetry about the origin.

When-2 < x <; 0，f(x)>0,

f(x)/x & lt； 0, the original inequality holds.

When x

f(x)/x & gt； 0, the original inequality does not hold.

To sum up, the solution set of inequality is

(-2，0)U(0，2)

The combined image is clearer.