Solution: domain: x>0, that is, x∈(0, +∞);

x→0+limy = x→0+lim(xlnx)= x→0+lim[(lnx)/( 1/x)]= x→0+lim[( 1/x)/(- 1/x？ )]

= x→0+lim(-x)= 0； ? y( 1)= 0； ? y(e)= e；

Let y'= 1+lnx=0 and lnx=- 1, so the stagnation point x =1/e; Y (1/e) = (1/e) ln (1/e) =-1/e (minimum value);

y ' ' = 1/x； X>y "is 0 > 0, so the curve in the domain (0, +∞) is concave upward.

The image is as follows: