Current location - Training Enrollment Network - Mathematics courses - The bid for the 24th International Congress of Mathematicians held in Beijing in August 2002 is shown below (1). It can be regarded as a straight line with four sides A, B and C.
The bid for the 24th International Congress of Mathematicians held in Beijing in August 2002 is shown below (1). It can be regarded as a straight line with four sides A, B and C.
Answer: Solution: (1) According to the meaning of the question, the area of the small square in the middle (b? a)2=? c2? 4×? 12ba;

Simplified to a2+b2=c2,

In other words, the square of the hypotenuse of a right triangle is equal to the sum of the squares of two right angles.

(2) As shown:

From the figure, we can get (a+b) 2 = C2+4× 12ab.

So A2+B2 = C2.

(3)c2=a2+b2=(a+b)2-2ab=49-24=25,

∴c=5.