Then because the yellow beads are odd, we should consider a special case, that is, the necklace is symmetrical from a yellow bead. In this case, the order after the necklace is turned over is still the order before it is turned over. C (5,2) * C (3,2) = 30 can be used to get the possible situation of one side of yellow beads, and the other side is symmetrically arranged.
Finally, directly use (630-30)/2+30=330, that is, divide by two on the basis of the scheme that is not asymmetric, and then directly accumulate symmetrically. As a result, there are 330 schemes to consider the capsizing situation, so choose B. If you have any questions, you can leave me a message.