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The problem of finding surface area in mathematics (fifth grade in primary school)
Let the length, width and height of a small cuboid be a, b and h respectively.

We know: a = 10/3 (decimeter)

B= 10/4 (decimeter)

C= 10/5=2 (decimeter)

The area of each cuboid is: (ab+bc+ac)x2.

S cuboid = (10/3x10/4+10/3x15+14x10/5) x2 = 40 (square.

S total =40X60=2400 (square decimeter)

Mine is right, and all the conditions given are used, not useless, but a kind of verification. I almost lost my mind just now because of you.

Tell us how much to cut, but tell us that the length, width and height of the final cuboid are all fractions of 10 decimeter. The method I use is to calculate the area of each small cuboid first and then multiply it by the total number of blocks.