Geometric problems of mathematical quadratic function

Let A(0, a)B(b, 0) a and b not be 0.

Then there is p (2/3b, 1/3a).

What about a? 6? 1a+b？ 6? 1b=m？ 6? 1m

So s triangle POB = 1/2? 6? 1b？ 6? 1 1/3a= 1/6？ 6? 1ab

Get a from mean inequality? 6? 1a+b？ 6? 1b > = (greater than or equal to) 2a? 6? 1b so s is less than or equal to112m? 6? 1m

When this equation holds, there is a = B.

AOB is an isosceles right triangle.

Ode to Happy Lesson Plan 1

Activity objectives:

1, which can be used to combine the outline image of characters with circles and ellipses.