The express train and the local train meet in 4 hours, and the express train runs at a speed of 50km/ h. From this question, we can know that the express train goes from B to A, and the local train goes from A to B at the same time, face to face and meet in 4 hours. After that, the local train continued to drive to the second place, and it took five hours to get to the second place. The distance in this process is four hours when the express train and the local train travel in opposite directions, so the speed ratio of the express train and the local train should be the inverse ratio of the time they spend on the same distance, that is, 5:4. Then, the express train speed is 50 km/h and the local train speed is 40 km/h.

Then the total distance of the movement in the opposite direction is (50km/h+40km/h) × 4h = 360km.

This is a question of mathematical logic thinking. Imagine that if car A and car B have the same speed, they will travel the same distance in the same 4 hours. However, if they meet at the midpoint 15km, then the distance difference between B and A cars during this period is 15×2km (this is the key point), (because the speed is the same). However, the express train not only covered the midpoint 15km, but also walked more after the midpoint/kloc-. So this express train travels 30km more than the local train, so the speed difference between the fast and slow trains is 30km/4 hours =7.5km, so the second train is 48.5km/ hour or 33.5km/ hour.

6. According to the meaning of the question, 17.5 yuan is by no means the cost generated by one hour, but can be regarded as the sum of the costs generated by parking in two time periods, of which the cost of 5 yuan was generated in the previous hour; The rest 12.5 yuan is produced by parking outside for one hour. The unit price of parking charge during this period is 2.5 yuan/half an hour, so the parking time during this period is: 12.5 yuan divided by 2.5 yuan/half an hour =5 and a half hours, which is equivalent to 2 hours and 30 minutes. So the total parking time in these two periods is 3 hours and 30 minutes.

7. Rectangular circumference = (length+width) ×2, as we know from the title: length =3× width, rectangular circumference =(3× width+width) ×2=4× width ×2=8× width = 36m, so width = 36m ÷ 8 = 4.5m, and length =

8. Average speed = total distance/total time, the total distance is twice that of Party A and Party B = 156km×2=3 12km, and the total time is the time from Party A to Party B+the time from Party B to Party A, so the total time is = 156 ÷ 40+6544. So the average speed =3 12÷6.5=48km/ hour.

9. This is a pursuit problem, and I have studied mathematics in elementary school. The specific answer can be: If A and B have the same speed, then B will never catch up with A, and only if B is faster than A can it catch up with A! When B catches up with A, the distance between B and A is 600 meters at first, which is equivalent to B walking 600 meters at a speed more than A in these six minutes (this is the key to solving the problem). So the speed of B is more than that of A =600 meters ÷6 minutes = 100 meters/minute. So the speed of B = the extra speed of B than A+the speed of A =100m/min+40m/min =140m/min.

10. This problem is also a pursuit problem. The car overtook the motorcycle at a speed higher than that of the motorcycle within 1.7 hours, and the distance that the car walked more than the motorcycle within this 1.7 hour is the distance that the motorcycle walked first. Therefore, the distance in front of the motorcycle = (vehicle speed-motorcycle speed) × time = (92-68 )× 1.7 = 40.8kmh, so the express train travels 200km to reach the meeting point, and the local train arrives at the second place five hours later, so the speed of the local train is 200/5=40km/h, and the distance between Party A and Party B is 40 *.

5. When two cars meet at the midpoint of 15, A drives 4*4 1= 164km to reach the meeting point, so the distance between the two places is (164+ 15)*2=358km, so the speed of B. Speed of B car: 200/5 = 40; B car * * * walked 4+5=9 hours; Distance between the two places: 40*9=360 km 5. When they meet, a car left: 4 1*4= 164, so the speed of b car has two situations: (164+ 15)/4=44.75 or (164-/. 17.5/2.5=5 5*0.5=2.5 hours 7. Let the width be x, then the length is 3x, (3x+x)*2=36 x=9/2 Length: 3*(9/2)=27/2 Area: (9/2)*(27/2)=243/4 8. * * * The exercise time is:156/40+156/60 = 3.9+2.6 = 6.5, and the average speed is (156+ 156)/6.5=48 9. A left: 40*6=240 B left: 240+600=840 A speed: 840/6= 140 10. The car went 92* 1.7= 156.4, and the motorcycle went 68 *1.7 =15.6. The distance between the two cars is156.4-115.6 = 40.8 degrees. After that, the local train continued to drive to the second place, and it took five hours to get to the second place. The distance in this process is four hours when the express train and the local train travel in opposite directions, so the speed ratio of the express train and the local train should be the inverse ratio of the time they spend on the same distance, that is, 5:4. Then, the express train speed is 50 km/h and the local train speed is 40 km/h.

Then the total distance of the movement in the opposite direction is (50km/h+40km/h) × 4h = 360km.

This is a question of mathematical logic thinking. Imagine that if car A and car B have the same speed, they will travel the same distance in the same 4 hours. However, if they meet at the midpoint 15km, then the distance difference between B and A cars during this period is 15×2km (this is the key point), (because the speed is the same). However, the express train not only covered the midpoint 15km, but also walked more/kloc-after the midpoint. So this express train travels 30km more than the local train, so the speed difference between the fast and slow trains is 30km/4 hours =7.5km, so the second train is 48.5km/ hour or 33.5km/ hour.

6. According to the meaning of the question, 17.5 yuan is by no means the cost generated by one hour, but can be regarded as the sum of the costs generated by parking in two time periods, of which the cost of 5 yuan was generated in the previous hour; The rest 12.5 yuan is produced by parking outside for one hour. The unit price of parking charge during this period is 2.5 yuan/half an hour, so the parking time during this period is: 12.5 yuan divided by 2.5 yuan/half an hour =5 and a half hours, which is equivalent to 2 hours and 30 minutes. So the total parking time in these two periods is 3 hours and 30 minutes.

7. Rectangular circumference = (length+width) ×2, as we know from the title: length =3× width, rectangular circumference =(3× width+width) ×2=4× width ×2=8× width = 36m, so width = 36m ÷ 8 = 4.5m, and length =

8. Average speed = total distance/total time, the total distance is twice that of Party A and Party B = 156km×2=3 12km, and the total time is the time from Party A to Party B+the time from Party B to Party A, so the total time is = 156 ÷ 40+6544. So the average speed =3 12÷6.5=48km/ hour.

9. This is a pursuit problem, and I have studied mathematics in elementary school. The specific answer can be: If A and B have the same speed, then B will never catch up with A, and only if B is faster than A can it catch up with A! When B catches up with A, the distance between B and A is 600 meters at first, which is equivalent to B walking 600 meters at a speed more than A in these six minutes (this is the key to solving the problem). So the speed of B is more than that of A =600 meters ÷6 minutes = 100 meters/minute. So the speed of B = the extra speed of B than A+the speed of A =100m/min+40m/min =140m/min.

10. This problem is also a pursuit problem. The car overtook the motorcycle at a speed higher than that of the motorcycle within 1.7 hours, and the distance that the car walked more than the motorcycle within this 1.7 hour is the distance that the motorcycle walked first. Therefore, the distance in front of the motorcycle = (vehicle speed-motorcycle speed) × time = (92-68 )×1.7 = 40.8km..

Meter/hour.

6. * * paid 17.5 MINUS the money payable in the first hour, which is 17.5-5= 12.5. An hour later, every half hour in 2.5 yuan is 12.5/2.5=5 (half an hour), so he stopped a * *.

7,2 * (length+width) =36, then length+width = 18, and 3* width = length, then 4* width = 18 means width 4.5, length 13.5 and area 60.75.

8. It takes 156/40=4.9 hours to get from A to B, and 156/60=2.6 hours to get from B to A, so the total driving time is 4.9+2.6=7.5 hours, and the total distance is156 * 2 = 365438.

9. If A goes 40*6=240m, then B goes 240+600=840m. If B catches up with A in 6 minutes, then B's speed is 840/6 = 140m per minute.

10, the total distance traveled by automobiles is 92* 1.7= 156.4km, so the total distance traveled by motorcycles is 156.4km, and the distance traveled by motorcycles in the process of chasing motorcycles is 68 *1.7 =/kloc.

The answer may not be correct in the process of solving, but the idea is correct. I hope it helps you. Thank you.

The express train and the local train leave from Party A and Party B at the same time, moving in opposite directions, and meet in 4 hours. It will take another five hours for the local train to reach B after the meeting. It is known that the express train runs at 50 kilometers per hour. How many kilometers are there between these two places?

Meeting time: 4 hours

The express train is 50 kilometers per hour, and 50*4=200. This is the distance traveled by the express train and the distance traveled after the local train meets. This is the key.

Find the local speed, and then use: (express speed+local speed) * meeting time = distance between the two places.

Two cars leave from two places at the same time. Four hours later, the two cars met at a distance of15km. The first car keeps 4 1 km per hour, and the second car keeps how many kilometers per hour?

Meeting time: 4 hours

A distance: 4 1*4= 164.

Meet at the midpoint of 15m, that is, 164- 15 is half the distance, 149. Here I assume that A is fast and take 149.

Then the distance of bus B is 149- 15.

Speed B: 149- 15/4

6. The charging standard of a parking lot is as shown on the right. My little dad paid 17.5 yuan. How many hours did he park in this parking lot?

charging standards

/kloc-5 yuan within 0/hour.

Exceeding 1 hour, every 0.5 hour 2.5 yuan.

2.5 yuan is 1 hour 5 yuan every 0.5 hours.

Let's set the equation: let's set it to stop for x hours. 17.5 is greater than 5, so it must be greater than 1 hour.

Overtime: (x- 1) hours =2(x- 1) 0.5 hours.

Overtime *2.5+ original 5 yuan = 17.5, that is, 2 (x-1) * 2.5+5 =17.5.

Solve the equation yourself! !

7. The circumference of a cuboid is 36 meters, and the known length is three times the width. What is the length and width of this rectangle? What is its area?

If the width is x meters, the length is 3x meters.

Rectangular perimeter =2 (length+width) = perimeter

Bring it in yourself.

8. The distance between Party A and Party B is156km. A car travels from Party A to Party B at a speed of 40 kilometers per hour, and immediately returns to Party A at a speed of 60 kilometers per hour after arriving at Party B.. How many kilometers does this car travel to and from the two places on average every hour?

Average speed = total distance/total time

The total distance is two 156 meters, because the round trip is 156*2.

Total time = time to go+time to come back.

Time to go = 156/40, time to return = 156/60. . . . Needless to say, time = distance/speed.

Then it can be solved. The key is to know the meaning of average speed: average speed = total distance/total time.

9.AB is 600 meters apart, and two people walk in the same direction from A and B at the same time. A is 40 meters each. After 6 minutes, B catches up with A and asks B's speed. ..

This is a catch-up problem. The general formula is: catching up time * speed difference = catching up distance.

Speed difference is the speed at which fast speed slows down. Here B catches up with A, so B is quick.

The catch-up distance is 600 meters.

The catch-up time is 6 minutes.

So the speed difference =600/6= 100 (m/min) and then the speed of Party A plus the speed difference is the speed of Party B (140m/min).

10. A car overtook the first motorcycle at a speed of 92 kilometers per hour. It is known that the speed of the motorcycle is 68 kilometers per hour, and the car 1.7 hours catches up with the motorcycle. How many kilometers did the motorcycle drive?

As above, use the same formula: catch-up time * speed difference = catch-up distance.

The first distance is the distance that the car has to chase, that is, the chasing distance.

Catch-up time: 1.7 hours

Speed difference: 92-68=24 (km/h)

Capture distance: 1.7*24

Finally, I sincerely hope I can help you. I won't. I need to draw more pictures.

It is important to master the basic formula.

Meet time * speed and = distance.

Catch-up time * speed difference = catch-up distance

! ! ! ! ! ! ! ! Must master