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In 2008, the ninth grade (1) mathematics examination paper in Haidian District, Beijing.
( 1)△=(3k- 1)^2-4*(k+ 1)(2k-2)=(k-3)^2》0

So there are two equal real roots or two unequal real roots.

(2) Use the root formula X =-(3k-1) (k-3)/2 (k+1).

X=- 1 or x=2( 1-k)/k+ 1, because the root is an integer and k is a positive integer,

So k= 1, 3