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Fifth grade mathematics, Volume II, Beijing Normal University Edition, applied problems.
Surface area 156 square decimeter = (length * height+width * height+length * width) *2.

The bottom area is 30 square decimeters = length * width.

Bottom circumference 32m = (length+width) *2

The upper and lower areas can be removed from the surface area of 156, that is, length * width *2. At this time, the sum of the front, rear, left and right areas is 156-30*2=96 square decimeters.

That is, length * width *2+ width * height *2=96,

According to the multiplicative distribution rate, the similar items are merged, and it is known that (length+width) * height *2=96 square decimeter.

We also know that (length+width) *2=32, so we can get the height: 96/32=3 decimeters, and then according to the cuboid volume = bottom area * height.

The volume is 30*3=90 cubic decimeters.

So the formula is: 30*2=60 (square decimeter)

(sum of top and bottom)

156-60=96 (square decimeter)

(sum of front, back, left and right)

96/32=3 (decimeter)

(Height of cuboid)

30*3=90 (m3)

(Last Bottom Area * Height)

The volume of this cuboid is 90 cubic meters.