2. The circumference of a square = side length ×4 C=4a.
3. Area of rectangle = length× width S=ab
4. square area = side length x side length s = a.a
5. Area of triangle = base × height ÷2 S=ah÷2.
6. parallelogram area = bottom x height S=ah
7. trapezoidal area = (upper bottom+lower bottom) × height ÷ 2s = (a+b) h ÷ 2.
8. Diameter = Radius× 2D = 2r Radius = Diameter ÷2 r= d÷2
9. The circumference of a circle = π× diameter = π× radius× 2c = π d = 2π r.
10, circular area = pi × radius× radius? =πr.r
1 1, the surface area of a cuboid = (length× width+length× height+width× height) × 2.
12, cuboid volume = length× width× height V =abh.
13, the surface area of the cube = side length× side length× ×6 S =6a.a
14, volume of cube = side length x side length x side length v = a.a.a
15, lateral area of cylinder = circumference of bottom circle × height S=ch.
16, surface area of cylinder = upper and lower bottom areas+lateral area s = 2π r+2π rh = 2π (d÷2)+2π (d÷2) h = 2π (c2÷2; π)+ch。
17, cylinder volume = bottom area × height v = shv = π rh = π (d ÷ 2) h = π (c ÷ 2 ÷ π) h.
18, the volume of the cone = bottom area × height ÷ 3v = sh ÷ 3 = π r h ÷ 3 = π (d ÷ 2) h ÷ 3 = π (c ÷ 2 ÷ π) h ÷ 3.
19, cuboid (cube, cylinder)
1, number of copies × number of copies = total number of copies/number of copies = total number of copies/number of copies = number of copies.
2. 1 multiple× multiple = multiple1multiple = multiple/multiple = 1 multiple
3. Speed × time = distance/speed = time/distance/time = speed
4. Unit price × quantity = total price ÷ unit price = total quantity ÷ quantity = unit price
5. Work efficiency × working hours = total workload ÷ work efficiency = working hours ÷ total workload ÷ working hours = work efficiency.
6. Appendix+Appendix = sum, and-one addend = another addend.
7. Minus-Minus = Minus-Minus = Minus+Minus = Minus
8. Factor × factor = product ÷ one factor = another factor.
9. Dividend = quotient dividend = divisor quotient × divisor = dividend
Calculation formula of mathematical graphics in primary schools
1, square c perimeter s area a side length perimeter = side length× 4c = 4a area = side length× side length s = a× a.
2. Cube V: volume A: side surface area = side length × side length× 6s table =a×a×6 volume = side length× side length× side length V = a× a× a.
3. rectangle c perimeter s area a side length perimeter = (length+width) ×2 C=2(a+b) area = length × width S=ab.
4. cuboid v: volume s: area a: length b: width h: height
(1) surface area (length× width+length× height+width× height )× 2s = 2 (AB+ah+BH)
(2) volume = length× width× height V=abh
5 triangle s area a base h height area = base x height ÷2 s=ah÷2 triangle height = area x 2 ÷ base triangle base = area x 2 ÷ height.
6 parallelogram s area a bottom h height area = bottom x height s=ah
7 trapezoid s area a upper bottom b lower bottom h height area = (upper bottom+lower bottom) × height ÷2 s=(a+b)× h÷2.
8 circle s area c perimeter ∏ d= diameter r= radius (1) perimeter = diameter x ∏ = 2 x ∏× radius c = ∏ d = 2 x r (2) area = radius x radius x ∏.
9 cylinder v: volume h: height s; Bottom area r: bottom radius c: bottom perimeter
(1) lateral area = bottom circumference × height.
(2) Surface area = lateral area+bottom area ×2
(3) Volume = bottom area × height
(4) Volume = lateral area ÷2× radius.
10 cone v: volume h: height s; Bottom area r: bottom radius volume = bottom area × height ÷3 Total number ÷ Total number of copies = average value.
Sum and difference problem (sum+difference) ÷ 2 = large number (sum and difference) ÷ 2 = decimal.
Sum multiplication problem sum ÷ (multiple-1) = decimal × multiple = large number (or Sum-Decimal = large number).
Difference problem ÷ (multiple-1) = decimal × multiple = large number (or decimal+difference = large number)
Tree planting problem 1 tree planting problem on unclosed line can be mainly divided into the following three situations:
(1) If trees are to be planted at both ends of the non-closed line, then: number of plants = number of segments+1 = total length ÷ plant spacing-1 = total length ÷ (number of plants-1).
⑵ If you want to plant trees at one end of the non-closed line and not at the other end, then: number of plants = number of segments = total length/plant spacing = plant spacing × plant spacing = total length/plant spacing.
(3) If no trees are planted at both ends of the closed line, then: number of plants = number of segments-1 = total length ÷ plant spacing-1 = total length × (number of plants+1) plant spacing = total length ÷ (number of plants+1).
The quantitative relationship of planting trees on the closed line is as follows: number of trees = number of segments = total length/plant spacing = plant spacing × number of trees = total length/plant spacing.
Profit and loss problem (surplus+deficit) ÷ Difference between two distributions = number of shares participating in distribution (large surplus-small surplus) ÷ Difference between two distributions = number of shares participating in distribution (large deficit-small deficit) ÷ Difference between two distributions = number of shares participating in distribution.
Meeting problem Meeting distance = speed and x meeting time Meeting time = Meeting distance ÷ Sum of speed and speed = Meeting distance ÷ Meeting time.
Catch-up problem Catch-up distance = speed difference × catch-up time Catch-up time = catch-up distance ÷ speed difference Speed difference = catch-up distance ÷ catch-up time
Downstream velocity = still water velocity+water velocity, countercurrent velocity = still water velocity-water velocity = (downstream velocity+countercurrent velocity) ÷2 Water velocity = (downstream velocity-countercurrent velocity) ÷2 Concentration problem Solute weight+solvent weight = solution weight ÷ solution weight × 100%.
Profit and discount problem Profit = selling price-cost profit rate = profit/cost×100% = (selling price/cost-1) × 100% increase or decrease = principal× percentage discount = actual selling price× original selling price× 65438+.
The time unit is converted into 1 century = 100 1 year =1February (3 1 day):1357810/February. Leap year: 366 days, 1 day =24 hours, 1 hour =60 minutes, 1 hour =60 seconds, 1 hour =3600 seconds product = bottom area × height V=Sh.