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The penultimate math problem in junior high school by combining number and shape in senior high school entrance examination
(1) Angle AOB=90 degrees, from the known OA=8, OB=6, so AB is the diameter of the circle m, AB= 10, so the radius is 5,m (4,3).

(2) The analytical formula of straight line AB is y=-3\4x+6, because the bisector of ∠BOA and AB intersect at point n and ⊙M intersect at point e, so the angle AOE is 45 degrees, the analytical formula of straight line OE is y=x, and let N(x, x) be x =-3 \ 4x. 7-4) square +(24\7-3) square ]=5\7. In the right triangle MNE, NE= radical sign [(5\7) square +5 square ]=25\7 radical sign 2, so OE=24\7 radical sign 2+25\7 radical sign 2 =