Known: As shown in the figure, take a point E outside the square ABCD and connect AE, BE and de. The vertical line passing through point A as AE intersects with point P, if AE=AP= 1, PB= root number 5. The following conclusions are drawn: (1) triangular APD is equal to triangular APD; (2) The distance from point B to the straight line is root number 2; (3)EB is perpendicular to the square root of ED(4)S triangle APD+S triangle APB = 1+6; (5) The square of s ABCD = the square root of 4+6. The serial number of the correct conclusion is (

)A. 134

B 125

C.345

D. 135