The addition of bits is still D, so D must be 0, and C is carried, so C is 1, and the addition of thousands is 0, so A is 5. If we analyze these ten digits, we can get that E is 4, and then we can see that B is 2.

Learning mathematics+using mathematics+learning mathematics well+learning mathematics well equals learning mathematics for use.

By adding thousands, we can know that the number = 1, by unit analysis, it may be 2, 4, 6, 8, and then by learning thousands, we can learn and carry, so we use =8, then learn =2, that is =4, and then by analyzing hundreds and thousands, we can produce a good =6.

X and y don't represent numbers, XY is a two-digit number, and YYY is a three-digit number ` if X*Y*XY equals YYY.

X*xy=yyy÷y can be obtained by x*y*xy=yyy, so when two numbers x * xy = 11are multiplied by one bit, there may be only1,or 9 and 9. Obviously, because X and Y represent different numbers, X and Y are 3 and 7.