1): oc vertical AP in C, OD vertical PB in D. ..
∵PA=PB ∴OC=OD (in the same circle or in the same circle, the centers of equal chords are equidistant)
∴∠APO=∠BPO (points with equal distance to both sides of the angle are on the bisector of the angle)
(2): OE and OF are perpendicular to AC and BD respectively.
∵AC=BD ∴OE=OF (in the same circle or in the same circle, the centers of equal chords are equidistant)
In δδOPE and OPF.
1。 OP=OP (common edge) 2. OE=OF (known) 3. ∠PEO=∠PFO=90 degrees
∴ΔOPE Δ OPF (HL) ∴∠ APO = ∠ BPO ∴∴∴ PO ∠APB.
(3)
Connect AO, OB
From the figure, we can get OA, OB is the radius of the circle, ∴OA=OB.
PA = PB (known) OP=OP (male * * * side)
∴ΔopA ≌ΔOPB (SSS) ∴∠ OPA = ∠ OPE, that is, OP shares ∠APB.