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Ask a math problem (permutation and combination)
Define each position:

B.C.

European development fund

G H I

First of all, the smallest number of position A can only be 1, and the largest number of position I can only be 9, as follows:

65438 BC

European development fund

G H 9

Of the remaining numbers, 2 is the smallest and can only be in the position of B or D..

1, assuming B=2, 3 can only be in position c or d.

1. 1, C=3, then d is the smallest of the remaining positions, only 4, which becomes:

1 2 3

4. Britain and France

G H 9

1. 1. 1: E=5, there are three kinds, namely:

1, 2,3 or: 1, 2,3 or: 1, 2,3.

4, 5, 6 or: 4, 5, 7 or: 4, 5, 8.

7,8,9; Or: 6, 8, 9 or 6, 7, 9.

1. 1.2: G=5, there are two kinds, namely:

1, 2,3 or: 1, 2,3,

4, 6, 7 or 4, 6, 8,

5,8,9; Or: 5, 7, 9,

When C=3, * * has 3+2=5 permutations.

1.2, D=3, then 4 is the smallest remaining position among c, e, G E and g.

1 2℃.

3 England and France

G H 9

1.2. 1: C=4, there are five kinds, namely:

1, 2,4 or: 1, 2,4 or: 1, 2,4 or: 1, 2,4.

3,5,6 or: 3,5,7 or: 3,5,8 or: 3,6,7 or: 3,6,8.

7,8,9; Or: 6, 8, 9, or 6, 7, 9, or 5, 8, 9, or 5, 7, 9.

1.2.2: E=4, there are six kinds, namely:

1, 2,5 or 1, 2,5 or 1, 2,5 or 1, 2,6 or 1, 2,6 or 1.

3, 4, 6 or 3, 4, 7 or 3, 4, 8 or 3, 4, 7 or 3, 4, 8 or 3, 4, 8.

7,8,9; Or: 6, 8, 9, or 6, 7, 9, or 5, 8, 9, or 5, 7, 9, or 5, 6, 9.

1.2.3: G=4, there are five kinds, namely:

1, 2,5 or: 1, 2,5 or: 1, 2,6 or: 1, 2,6 or: 1, 2,7.

3, 6, 7 or 3, 6, 8 or 3, 5, 7 or 3, 5, 8 or 3, 5, 8.

4,8,9; Or: 4,7,9, or: 4,8,9, or: 4,7,9, or: 4,6,9.

When D=3, a * * * has: 5+6+5= 16 methods.

When B=2, there are: 5+ 16=2 1 methods.

2. When D=2, there are also 2 1 methods.

A * * * has 2 1*2=42 permutations.