1) If the environment is bright, it is difficult to see the virtual image of the candle through the glass;

2) The fewer candles, the shorter, that is, the upper end is close to the lower end; For inverted images, the lower end is close to the upper end, which is called moving up;

3) An inverted enlarged real image appears, indicating that F.

4) Draw a light path diagram, and it will be clear to compare the two situations;

5) The solution of10/r-6/r = 0.1a has r = 40ω△ p =100/r-36/r =1.6w.

6) Both are electromagnetic waves, and the main difference is that the wavelength decreases from left to right.