Give a set of numbers and fill in the three sides of the triangle respectively to make the sum of each side equal. First, add all the numbers together to find the sum, and see if it can be divisible by 3. Then determine the numbers on the three vertices, and the sum of the numbers on the three vertices must be a multiple of 3. List all cases separately, and then determine the vertex. The sum of each edge is the sum plus three vertices, and then all the values are determined.

For example, 1 to 6 should be filled in the six spaces of three sides of a triangle, so that the sum of each side is equal. The solution is 1+2+3+4+5+6=2 1, and 2 1 is divisible by 3, so the sum of the three vertices is also a multiple of 3. From 6 numbers from 1 to 6, choose 3 numbers to make the sum a multiple of 3.

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Because the sum of each row is required to be 12, and the number given is not 1, and the position of 2 in the question has been fixed, it is necessary to ensure that the sum of the two numbers is less than 1 1. Of the three numbers given, 6+7= 13, 5+7= 12, 5+6= 1 1, 4+7 =1.

After exclusion, there are still combinations of 3+4 = 7, 3+5 = 8, 3+6 = 9, 3+7 = 10, 4+5+9 and 4+6= 10. According to the known position of 2, we can also determine 3, 7, 4 and 6.