When x=0, substitute 1 and 3 respectively, f(0)=-abc, f( 1)=4-abc, and f(3)=-abc, so f (0) f (1) = (-ABC) (. The answer is C. In fact, it is easy to see that f(0)f(3)> 0, and because the function has three intersections with the X axis, f( 1) is opposite to f(3), and f(0)f(3)> 0, so f(0) is the same as f(3), so f(0)