Solution: Let the coordinate of the point be P(x, y),
What is the square of the distance from point p to o? x^2+y^2
The square of the distance from point p to a is (x-c) 2+y 2.
x^2+y^2-(x-c)^2-y^2=c
Get 2cx = c+c 2.
Then the trajectory is x=( 1+c)/2.
2.
Establish a rectangular coordinate system with the midpoint of two fixed points as the origin.
The coordinates of the two fixed points are (-3,0) (3,0) respectively.
Let the coordinates of point M be (x, y).
Yes: (x+3) 2+y 2+(x-3) 2+y 2 = 26.
x^2+y^2=4
M-point trajectory is round?
3.
I just drew a circle, okay? And the main conditions may be embarrassed to come.