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Ask for advice on math problems: A and B have two piles of Go. ...
There is Bai Zi 3/(4/7- 1/2) = 42 in heap a.

There are sunspots 42 * 1/2 = 2 1 (pieces).

The number of albinos is 42-2 1 = 2 1 (one) more than sunspots.

Therefore, the B-pile has 2 1 sunspot more than the albino star.

So * * * 21[(7-4)/(7+4)] = 77 pieces.

There are 42+2 1 = 63 in the armor pile.