The answer? In the picture:

2.

The inequality in (1)b can be simplified as:

(x-2m)(x- 1)& lt； 0? Because m

So what? 2m & ltx & lt 1

B = { x | 2m & ltx & lt 1},

②

From A∪B=A== >b is a subset of a;

I) If b is an empty set, the discriminant is ≤0.

Namely: (2m+1) 2-8m ≤ 0 = >; (2m- 1)^2≤0？ = = & gtm= 1/2

Ii) If b is not an empty set,

Because one of them is? 1

Just another one? 2m conforms to:

- 1≤2m≤2； ? That is-1/2≤m≤ 1.

Generally speaking:

m∈？