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The answers to the exercises in the first volume of the eighth grade mathematics textbook published by People's Education Press.
1.DA=EB
It is proved that in Rt△DAC and Rt△EBC {CD=CE (known) AC=BC (known)} \
2. It is proved that ∫AE⊥BC df⊥BC∴∠DFC = 90∠aeb and ∫ CE-Fe = BF-Fe, that is, CF=BF is in Rt△DFC and Rt△AEB.