∴ Derive the curve: y' = 3x 2- 10, and the derivative value y' is the slope 2.
∴ 3x 2- 10 = 2, x=2 or -2.
Point p is in the second quadrant.
∴x=-2, if substituted into the curve equation, y = (-2) 3-10 * (2)+3 =15.
The coordinate of point p is P(-2, 15).