∴ Derive the curve: y' = 3x 2- 10, and the derivative value y' is the slope 2.

∴ 3x 2- 10 = 2, x=2 or -2.

Point p is in the second quadrant.

∴x=-2, if substituted into the curve equation, y = (-2) 3-10 * (2)+3 =15.

The coordinate of point p is P(-2, 15).